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Question


From the point O (2,3), tangents OP, OQ are drawn to circle x2+y2=1. Equation to the linejoining the midpoint of OP and OQ is

A
2x+3y=7
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B
3x+2y=7
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C
x+2y=3
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D
2x+y=3
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Solution

The correct option is A 2x+3y=7
eqn of chord of contact from O(2,3) to x2+y2=1
2x+3y=1
So, x=13y2
(13y2)2+y2=1
9y26y+1+4y2=1
13y26y=0
y=0 or y=613
So, x=12 or x=526
So, p(12) and (526,613)
So, mid point of of is m(54,34)
and mid - point of O is N(4752,4526)
So, eqn of line joining M N,
3y+2x=7

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