From the reaction, $2 N O_{2}$ $+$ $F_{2}$ $=$ $2 N O_{2} F$ , the rate expression according to the law of mass action depends on :

The square of the concentration of Nitrogen Dioxide

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Only on the concentration of Fluorine

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Only on the concentration of Nitrogen Dioxide

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Both on the square of the concentration of Nitrogen dioxide, and on the concentration of Fluorine raised to the power of one

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Solution

The correct option is D Both on the square of the concentration of Nitrogen dioxide, and on the concentration of Fluorine raised to the power of one
The reaction $2 N O_{2}$ $+$ $F_{2}$ $=$ $2 N O_{2} F$ , the rate expression according to the law of mass action can be written as-
$R a t e$ $=$ $k$ $[N O_{2}]^{2}$ $[F_{2}]$
Thus, it depends on the square of the concentration of Nitrogen dioxide and on the concentration of Fluorine raised to the power of one.

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