From the schematic electric field lines, we can infer that

the left charge is higher in magnitude than the right one

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the left charge is lower in magnitude than the right one

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the left charge is equal in magnitude to the right one

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None of these

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Solution

The correct option is B the left charge is lower in magnitude than the right one
Since, number of field lines denstiy and hence electric field is lower near left positive charge. Hence, magnitude of charge is lower on left charge than right one.

Answer-(B)

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Similar questions

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The electric field due to a charge at a distance of $3 m$ from it is $500 N / C$ . The magnitude of the charge is $[\frac{1}{4 π ε_{0}} = 9 \times 10^{9} N m^{2} / C^{2}]$ :

The electric field due to a charge at a distance of 3 m from it is 500 N/coulomb. The magnitude of the charge is $[\frac{1}{4 π ϵ_{0}} = 9 \times 10^{9} \frac{N - m^{2}}{c o u l o m b^{2}}]$

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From the schematic electric field lines, we can infer that

The correct option is B the left charge is lower in magnitude than the right oneSince, number of field lines denstiy and hence electric field is lower near left positive charge. Hence, magnitude of charge is lower on left charge than right one.Answer-(B)

The correct option is B the left charge is lower in magnitude than the right one
Since, number of field lines denstiy and hence electric field is lower near left positive charge. Hence, magnitude of charge is lower on left charge than right one.

Answer-(B)