MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Equilibrium Constant from Nernst Equation

From the stan...

Question

From the standard electrode potential values of the electrodes given select an option representing their decreasing order discharge potential:
$(a) A, E^{o} = 2.32 V$ $(b) B, E^{o} = 1.36 V$
$(c) C, E^{o} = 1.07 V$ $(c) D, E^{o} = 0.43 V$

A

a c b d

No worries! We‘ve got your back. Try BYJU‘S free classes today!

B

a b c d

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

C

a d b c

No worries! We‘ve got your back. Try BYJU‘S free classes today!

D

a b d c

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is D $a b c d$
The more positive the potential is the more likely it will be discharged. Thus decreasing order discharge potential would be $a b c d$ .
$(a) A, E^{o} = 2.32 V$ $(b) B, E^{o} = 1.36 V$
$(c) C, E^{o} = 1.07 V$ $(d) D, E^{o} = 0.43 V$

Suggest Corrections

thumbs-up

0

Similar questions

Q. Pairs of electrodes and their corresponding standard electrode potentials are given. Arrange the cells constructed by these electrodes in increasing order of emf values.

(a) E l e c t r o d e \to A, E^{o} = - 2.92 V

E l e c t r o d e \to B, E^{o} = - 2.71 V

(b) E l e c t r o d e \to C, E^{o} = - 0.760 V

E l e c t r o d e \to D, E^{o} = - 0.44 V

(c) E l e c t r o d e \to B, E^{o} = - 2.71 V

E l e c t r o d e \to D, E^{o} = - 0.44 V

(d) E l e c t r o d e \to A, E^{o} = - 2.92 V

E l e c t r o d e \to C, E^{o} = - 0.76 V

Q. The standard electrode potentials of the electrodes are given below. Arrange them in decreasing order of ease of oxidation:

(a) E l e c t r o d e - I, E^{o} = - 2.89 V

(b) E l e c t r o d e - I I, E^{o} = - 0.16 V

(c) E l e c t r o d e - I I I, E^{o} = 0.77 V

(d) E l e c t r o d e - I V, E^{o} = - 2.93 V

(e) E l e c t r o d e - V, E^{o} = - 1.67 V

Q. Given standard electrode potentials :

{F e}^{3 +} + {3 e}^{-} ⟶ F e; E^{o} = - 0.036 v o l t

{F e}^{2 +} + {2 e}^{-} ⟶ F e; E^{o} = - 0.440 v o l t

The standard electrode potential

E^{o}

{F e}^{3 +} + e^{-} ⟶ {F e}^{2 +}

Q. Given, standard electrode potentials,

F e^{2 +} + 2 e^{-} \to F e, E^{o} = - 0.440

F e^{3 +} + 3 e^{-} \to F e, E^{o} = - 0.036

The standard electrode potential

(E^{o})

F e^{3 +} + e^{-} \to F e^{2 +}

Q. Given standerd electrode potentials

F e^{2 +} + 2 e^{-}

⟶

F e; E^{o} = - 0.440 V

F e^{3 +} + 3 e^{-}

⟶

F e; E^{o} = - 0.036 V

The standard electrode potential

(E^{o}

F e^{3 +} + e^{-}

\to

F e^{2 +}

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Equilibrium Constant from Nernst Equation

CHEMISTRY

Watch in App

explore_more_icon

Explore more

Equilibrium Constant from Nernst Equation

Standard XII Chemistry

Join BYJU'S Learning Program

CrossIcon