From the standard form of the circle equation $(x - 4)^{2} + (y + 3)^{2} = 25$ . Find its center.

(4, 3)

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(- 4, - 3)

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(- 4, 3)

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(4, - 3)

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Solution

The correct option is B $(4, - 3)$
Compare the equation with the standard form with center at $(h, k)$ is: $(x - h)^{2} + (y - k)^{2} = r^{2}$
$(x - 4)^{2} + (y + 3)^{2} = 25$
Therefore, center of $(h, k) = (4, - 3)$

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