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Byju's Answer
Standard IX
Mathematics
(x±a)(x±b) = x²±(a+b)x+ab.
From the sum ...
Question
From the sum of z
3
+ 3z
2
+ 5z + 8 and 4z
3
+ 2z
2
-
7z
-
2 subtract 2x
3
-
3z
2
+ z
-
4.
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Solution
Required
polynomial
=
z
3
+
3
z
2
+
5
z
+
8
+
4
z
3
+
2
z
2
-
7
z
-
2
-
2
z
3
-
3
z
2
+
z
-
4
=
z
3
+
3
z
2
+
5
z
+
8
+
4
z
3
+
2
z
2
-
7
z
-
2
-
2
z
3
+
3
z
2
-
z
+
4
=
z
3
+
4
z
3
-
2
z
3
+
3
z
2
+
2
z
2
+
3
z
2
+
5
z
-
7
z
-
z
+
8
-
2
+
4
=
3
z
3
+
8
z
2
-
3
z
+
10
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0
Similar questions
Q.
Subtract
3
x
y
+
2
z
2
from
5
x
y
+
3
z
2
−
x
z
Q.
Subtract the polynomial
z
2
–
2
z
+
4
from
3
z
2
−
7
.
Q.
If
|
z
1
|
=
2
,
|
z
2
|
=
3
,
|
z
3
|
=
4
a
n
d
|
2
z
1
+
3
z
2
+
4
z
3
|
=
4
,
then absolute value of
8
z
2
z
3
+
27
z
3
z
1
+
64
z
1
z
2
equals
Q.
If
|
z
1
|
=
2
,
|
z
2
|
=
3
,
|
z
3
|
=
4
and
|
2
z
1
+
3
z
2
+
4
z
3
|
=
10
, then absolute value
8
z
2
z
3
+
27
z
3
z
1
+
64
z
1
z
2
must be equal to-
Q.
If
z
=
2
+
i
and
z
3
+
3
z
2
−
9
z
+
8
=
a
+
i
b
, then the value of
a
+
b
is
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(x±a)(x±b) = x²±(a+b)x+ab.
Standard IX Mathematics
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