From the thermo chemical reactions- Cgraphite-1-2O2- CO- H-110-5KJ CO-1-2O2- CO2- H-283-2KJ- - H for the reaction- Cgraphite-O2- CO2 is-

The correct option is A 393.7 KJC (graphite) + #160; 1/2O_2→ CO Δ H= 110.5KJ CO+1/2O_2→ CO_2 Δ H= 283.2KJ Adding we get,C (graphite) + #160; ...

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Enthalpy of Combustion

From the ther...

Question

From the thermo chemical reactions,
$C_{(g r a p h i t e)} + \frac{1}{2} O_{2} \to C O; Δ H = - 110.5 K J$
$C O + \frac{1}{2} O_{2} \to C O_{2}; Δ H = - 283.2 K J .$
$Δ H$ for the reaction, $C_{(g r a p h i t e)} + O_{2} \to C O_{2}$ is:

-393.7 KJ

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+393.7 KJ

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-172.7 KJ

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+172.7 KJ

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C (g r a p h i t e) + O_{2} (g) ⟶ C O_{2} (g); Δ H = - 393.7 k J

C (d i a m o n d) ⟶ C (g r a p h i t e); Δ H = - 2.1 k J

Δ H

C O_{2}

C_{(g r a p h i t e)} + \frac{1}{2} O_{2} \to C O; Δ H = - 110.5 k J

C O + \frac{1}{2} O_{2} \to {C O}_{2}; Δ H = - 283.2 k J

C_{(g r a p h i t e)} + O_{2} \to {C O}_{2}

C (g r a p h i t e) + \frac{1}{2} O_{2} \to C O Δ H_{1} = - 110.5 k J / m o l

C O + \frac{1}{2} O_{2} \to C O_{2} Δ H = - 283.2 k J / m o l

k J / m o l

C (g r a p h i t e) + O_{2} \to C O_{2} Δ H = ?

C

+ \frac{1}{2} O_{2} \to C O; Δ H = - 110.5

C O + \frac{1}{2} O_{2} \to C O_{2}; Δ H = - 283.2

C (graphite) + O_{2} \to C O_{2}

From the thermochemical reactions,

C + 1/2O₂ → CO; ∆H = -110.5 kJ

CO + 1/2O₂→ CO₂; ∆H = -283.2 kJ

The heat of reaction C + O₂ → CO₂ is:

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