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Question

From the top of a 11 m high tower, a stone is projected with speed 10 m/s, at an angle of 37 with the horizontal as shown in the figure. Find
a) Time of flight.
b) Horizontal range.
c) Speed just before striking the ground.
(Take g=10 m/s2)


A
(a) 115 s, (b) 885 m, (c) 85 m/s
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B
(a) 1 s, (b) 8 m, (c) 85 m/s
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C
(a) 115 s, (b) 885 m, (c) 45 m/s
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D
(a) 1 s, (b) 8 m, (c) 45 m/s
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Solution

The correct option is B (a) 1 s, (b) 8 m, (c) 85 m/s
ux=10cos37=8 m/s,uy=10sin37=6 m/s

a) Using second equation of motion
Sy=uyt+12ayt211=6×t+1/2×(10)t2
5t2+6t11=0
(t1)(5t+11)=0
t=1 sec (taking positive value)

b) Range =ux×t=8×1=8 m

c) Speed just before striking the ground v=v2x+v2y=u2x+u2y+2gh=(8)2+(6)2+2×(10)×(11)=100+2×10×11
v=320 m/s=85 m/s

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