From the top of a building $h$ metre high, the angle of depression of an object on the ground has a measure $θ$ . The distance of the object from the building is

h cos θ

metre

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h sin θ

metre

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tan θ

metre

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h cot θ

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Solution

The correct option is C $h cot θ$
Height of the building is AB $= h$ metre and the object is located at point $C$

Now, $tan θ = \frac{opposite side}{adjacent side}$

$tan θ = \frac{h}{adjacent side}$

We need to find the adjacent side,

$⟹ adjacent side = \frac{h}{tan θ} = h cot θ$

Hence, the answer is $h cot θ$ .

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From the top of a building h metre high, the angle of depression of an object on the ground has a measure θ. The distance of the object from the building is

The correct option is C hcotθHeight of the building is AB =h metre and the object is located at point CNow, tanθ=opposite sideadjacent side tanθ=hadjacent sideWe need to find the adjacent side,⟹adjacent side=htanθ=hcotθHence, the answer is hcotθ.

From the top of a building $h$ metre high, the angle of depression of an object on the ground has a measure $θ$ . The distance of the object from the building is