From the top of a building of height h- the angle of depression of an object on the ground is - What is the distance of the object from the foot of the building in terms of h and -

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Calculating Heights and Distances

From the top ...

Question

From the top of a building of height $h,$ the angle of depression of an object on the ground is $θ .$ What is the distance of the object from the foot of the building in terms of $h$ and $θ ?$

h cot θ

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

h tan θ

No worries! We‘ve got your back. Try BYJU‘S free classes today!

h cos θ

No worries! We‘ve got your back. Try BYJU‘S free classes today!

h sin θ

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $h cot θ$
Let $x$ be the distance of the object from the foot of the building, we have

$tan θ = \frac{h}{x}$

$\Rightarrow x = h cot θ$

Hence, option $A$ is correct.

Suggest Corrections

Similar questions

Q. From the top of a building

h

metre high, the angle of depression of an object on the ground has a measure

θ

. The distance of the object from the building is

Q. Suppose you are shooting an arrow from the top of a building at a height of

6 m

to a target on the ground at an angle of depression of

60^{\circ}

. What is the distance between you and the object?

Q. The width of a road is

b

feet., on one side of which there is a window

h

feet height. A building in front of it subtends an angle

θ

at it. Prove that the height of the building is

\frac{(b^{2} + h^{2}) sin θ}{b cos θ + h sin θ}

A man 1.8 metres tall, looking down from the top of a telephone tower sees the top of a building 10 metres high at an angle of depression 40° and the foot of the building at an angle of depression 60°. What is the height of the tower? How far is it away from the building?

Join BYJU'S Learning Program

From the top of a building of height h, the angle of depression of an object on the ground is θ. What is the distance of the object from the foot of the building in terms of h and θ?

The correct option is A hcotθLet x be the distance of the object from the foot of the building, we havetanθ=hx ⇒x=hcotθ Hence, option A is correct.

From the top of a building of height $h,$ the angle of depression of an object on the ground is $θ .$ What is the distance of the object from the foot of the building in terms of $h$ and $θ ?$

The correct option is A $h cot θ$
Let $x$ be the distance of the object from the foot of the building, we have

$tan θ = \frac{h}{x}$

$\Rightarrow x = h cot θ$

Hence, option $A$ is correct.