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Question

From the top of a tower, a stone is thrown up and reaches the ground in time t1 . A second stone is thrown down with the same speed and reaches the ground in time t2. A third stone is released from rest and reaches the ground in time t3 -

A
t3=12(t1+t2)
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B
t3=t1t2
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C
1t3=1t21t1
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D
t23=t21t22
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Solution

The correct option is B t3=t1t2
Applying equations of motion for all three cases
h=ut112gt21...(1)
h=ut212gt22...(2)
&h=12gt23...(3)
Multiply equation 1 with t2 and equation 2 with t1 and add them
We get,
h=12gt1t2.......(4)
Now by (3) & (4)
t23=t1t2
t3=t1t2

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