From the top of a tower, a stone is thrown up. It reaches the ground in 5s. A second stone is thrown down with the same speed and reaches the ground in 1s. A third stone is released from rest and reaches the ground in
A
3 s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
2 s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
√5s
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
2.5 s
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is C√5s let height of tower is H, acceleration due to gravity is a,
case 1) initial velocity is −u (assuming downward direction as positive.
then H=−ut+12at2=>H=−5u+252a
for case 2) initial velocity is u
then H=ut+12at2=>H=u+12a
multiplying 2nd with 5 and adding both equation we get