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Question

From the top of a tower, a stone is thrown up. It reaches the ground in 5 s. A second stone is thrown down with the same speed and reaches the ground in 1 s. A third stone is released from rest and reaches the ground in

A
3 s
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B
2 s
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C
5 s
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D
2.5 s
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Solution

The correct option is C 5 s
let height of tower is H, acceleration due to gravity is a,
case 1) initial velocity is u (assuming downward direction as positive.
then H=ut+12at2=>H=5u+252a
for case 2) initial velocity is u
then H=ut+12at2=>H=u+12a
multiplying 2nd with 5 and adding both equation we get
6H=15a=>H=2.5a
now for 3rd case u=0, we get 2.5a=12at2=>t=5sec.

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