wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

From the top of a tower of height 200 m, a ball A is projected up with 10 ms1 and 2 s later another ball B is projected vertically down with the same speed. Then (Neglect air friction)

A
Both A and B will reach the ground simultaneously
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
Ball A will hit the ground, 2 s after B hits the ground
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
Both the balls will hit the ground with the same velocity
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
Both the balls will hit the ground with the different velocity
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C Both the balls will hit the ground with the same velocity
Ball A will return to the top of tower after
T=2ug=2×1010=2 s
with a speed of 10 ms1 downward.
And at the same moment B is also projected downward with 10 ms1.
So both reach ground simultaneously. Also they will hit the ground with same speed.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon