From the top of cliff 200ft. high, the angles of depression of the top and bottom of a tower are observed to be 30o and 60o respectively. Find the height of the tower.
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Solution
Let PQ=h be the height of tower angles of depression of Q and P are 30o and 60o as seen from top B of cliff AB of height 200ft. Let AP=x. 200−h=xtan30=x/√3;△BQR. 200=xtan60=√3x;△BPR. Dividing, we get 200−h200=13 or 3(200−h)=200 or 4003h ∴h=4003ft.