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Question

From the top of cliff 200 ft. high, the angles of depression of the top and bottom of a tower are observed to be 30o and 60o respectively. Find the height of the tower.

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Solution

Let PQ=h be the height of tower angles of depression of Q and P are 30o and 60o as seen from top B of cliff AB of height 200 ft.
Let AP=x.
200h=xtan30=x/3;BQR.
200=xtan60=3x;BPR.
Dividing, we get 200h200=13
or 3(200h)=200
or 400 3h
h=4003 ft.
1084323_1006315_ans_b17f5d8cab8b4672a2142cf920e80554.png

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