Question

From the uniform disc of radius R, an equilateral triangle of side $R\sqrt[]{2}$ is cut as shown in the figure. The new position of centre of mass is:

• A. ( 0,0)
• B. ( 0, R )
• C. (0 ,R/2)
• D. None of these

Answer 1

The correct option is A ( 0,0)

From the figure, we can see that, the triangle can be only by taking the centroid of the triangle at the centre of the circle.

Thus, the moment of inertia of the lamina will not disturb and will remain at (0, 0).