From the velocity time graph of a particle given in the figure, describe the motion of the particle in the interval 0 to 4 sec. Find the acceleration at $t = 2 s$ .

10 m/s

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-10 m/s

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15 m/s

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-15 m/s

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Solution

The correct option is B -10 m/s
Slope of v-t graph gives the acceleration of the particle for a given time interval.
Thus slope of line AC is equal to the acceleration of particle at $t = 2$ s.
$∴$ Acceleration $a {∣ ∣ ∣}_{t = 2 s} = \frac{- 10 - 10}{3 - 1} = - 10$ $m / s^{2}$

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From the velocity time graph of a particle given in the figure, describe the motion of the particle in the interval 0 to 4 sec. Find the acceleration at t=2s .

The correct option is B -10 m/sSlope of v-t graph gives the acceleration of the particle for a given time interval.Thus slope of line AC is equal to the acceleration of particle at t=2s.∴ Acceleration a∣∣∣t=2s=−10−103−1=−10 m/s2

From the velocity time graph of a particle given in the figure, describe the motion of the particle in the interval 0 to 4 sec. Find the acceleration at $t = 2 s$ .

The correct option is B -10 m/s
Slope of v-t graph gives the acceleration of the particle for a given time interval.
Thus slope of line AC is equal to the acceleration of particle at $t = 2$ s.
$∴$ Acceleration $a {∣ ∣ ∣}_{t = 2 s} = \frac{- 10 - 10}{3 - 1} = - 10$ $m / s^{2}$