From the velocity-time plot shown in figure, find the distance travelled by the particle during the first 40 seconds. Also find the average velocity during this period.

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Solution

Distance in first 40 sec = $Δ O A B + Δ B C D$
= $\frac{1}{2} \times 5 \times 20 + \frac{1}{2} \times 5 \times 20$
=50+50
=100 m

Average velocity is O as the displacement is zero.

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From the velocity-time plot shown in figure, find the distance travelled by the particle during the first 40 seconds. Also find the average velocity during this period.

Distance in first 40 sec =ΔOAB+ΔBCD =12×5×20+12×5×20 =50+50 =100 m Average velocity is O as the displacement is zero.

Distance in first 40 sec = $Δ O A B + Δ B C D$
= $\frac{1}{2} \times 5 \times 20 + \frac{1}{2} \times 5 \times 20$
=50+50
=100 m

Average velocity is O as the displacement is zero.