From what minimum height h must the system be released when spring is unstretched so that after perfectly inelastic collision (e = 0) with ground, B may be lifted off the ground (spring constant = k) from figure.

mg/(4k)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

4mg/k

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

mg/(2k)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

none of the above

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B
4mg/k

For lifting of 2m block

kx = 2mg …… (i)

By energy conservation

$m g (h - x) = \frac{1}{2} k x^{2}$ …… (ii)

From (i) and (ii)

$h = \frac{4 m g}{k}$

Suggest Corrections

Similar questions

From what minimum height h must the system be released when a spring is unstretched so that after perfectly inelastic collision (e=0) with ground, B may be lifted off the ground (spring constant =k)

Q. From what minimum height h must the system be released when a spring is unstretched so that after perfectly inelastic collision (e = 0) with ground, B may be lifted off the ground (spring constant = k).

Q. From what minimum height

^{'} h^{'}

should the system be released when the spring is unstretched so that after a perfectly inelastic collision (

e = 0

) with ground,

^{'} B^{'}

may be lifted off the ground (spring constant

= k

)

Q. The minimum height h,through which the system be released from rest and the spring is unstretched initially,is

\frac{x m g}{k}

.And collision between block B and surface is perfectly inelastic,such as after collision between B and ground 'B' may be lifted off from the ground after collision then x is:
(spring constant=k)

An ideal spring with spring-constant k is hung from the ceiling and a block of mass M is attached to its lower end. The mass is released suddenly with the spring initially unstretched. Then the maximum extension in the spring is

Join BYJU'S Learning Program

From what minimum height h must the system be released when spring is unstretched so that after perfectly inelastic collision (e = 0) with ground, B may be lifted off the ground (spring constant = k) from figure.

The correct option is B 4mg/k For lifting of 2m block kx = 2mg …… (i) By energy conservation mg(h−x)=12kx2 …… (ii) From (i) and (ii) h=4mgk

The correct option is B
4mg/k

For lifting of 2m block

kx = 2mg …… (i)

By energy conservation

$m g (h - x) = \frac{1}{2} k x^{2}$ …… (ii)

From (i) and (ii)

$h = \frac{4 m g}{k}$