Question

$\mathrm{From}\mathrm{what}\mathrm{number}\mathrm{should}2\frac{2}{3}\mathrm{be}\mathrm{subtracted}\mathrm{so}\mathrm{that}\mathrm{the}\mathrm{difference}\mathrm{would}\mathrm{be}6\frac{1}{3}?$

Answer 1

$\mathrm{Let}\mathrm{the}\mathrm{number}\mathrm{from}\mathrm{which}2\frac{2}{3}\mathrm{be}\mathrm{subtracted}\mathrm{from}\mathrm{be}x.\mathrm{According}\mathrm{to}\mathrm{the}\mathrm{question},x-2\frac{2}{3}=6\frac{1}{3}\Rightarrow x-\frac{3\times 2+2}{3}=\frac{6\times 3+1}{3}\Rightarrow x-\frac{8}{3}=\frac{19}{3}\Rightarrow x=\frac{19}{3}+\frac{8}{3}=\frac{19+8}{3}=\frac{27}{3}=9$