Question

Front side wall of a house consists of a rectangle of $6$ m $\times$ $4$ m surrounded by a semicircle with base $4$ m It has two isosceles triangles make with vertical sides of the rectangle The net area of the wall in sq m is :

• A. $4(15+\pi )$
• B. $4(18+\pi )$
• C. $4(24+\pi )$
• D. $64+4\pi$

Answer 1

The correct option is A $4(15+\pi )$

Net area of wall$=2\times$ area of triangle + area of rectangle+area of semi circle

$=2\times \frac{1}{2}\times base\times height+length\times breadth+\frac{1}{2}\pi r^2$

$=2\times \frac{1}{2}\times 6\times 6+6\times 4+\pi \times {\left(2\right)}^2$

$=36+24+4\pi$

$=60+4\pi$

$=4(15+\pi )m^2$