Fructose 1 : 6 biphosphate splits into two triose phosphates by enzyme

Aldolase

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Amylase

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Zymase

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Lipase

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Solution

The correct option is B Aldolase
In the process of glycolysis, the molecule of glucose is phosphorylated twice to form fructose-1,6-biphosphate. It is then acted upon by aldolase and splits into two triose phosphates: 3-phosphoglyceraldehyde and dihydroxyacetone phosphate. Both these compounds are tautomers in dynamic equilibrium and can interchange in presence of phosphotriose isomerase.
So the answer is 'Aldolase'.

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Similar questions

List-I (Enzyme)	List-II( Conversions)
a. Phosphogluco isomerase	$1$ . Fructose $\to$ Glucose
b. Triose phosphate isomerase	$2$ . Glucose $\to$ Glucose- $6$ -Phosphate
c. Fructose diphosphate aldolase	$3$ . Glucose- $6$ -phosphate $\to$ Fructose- $6$ -phosphate
d. Hexokinase	$4$ . Glyceraldehydes- $3$ -phosphate $\to$ Dihydroxy acetone phosphate
	$5$ . Fructose- $1$ , $6$ -diphosphate $\to$ Glyceraldehydes- $3$ -phosphate

	List I		List II
A	Hexokinase	1	Conversion of fructose-6-phosphate to fructose-1-6-diphosphate
B	Triose phosphate dehydrogenase	2	Conversion of glucose to glucose-6-phospahte
C	Phosphoglyceromutase	3	Conversion of 1, 3-diphosphoglyceraldehyde to 1, 3-diphosphoglyceric acid
D	Phosphofructokinase	4	Conversion of 3-phosphoglyceric acid to 2-phosphoglyceric acid

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