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Question

Function f(x) = x3 − 27x + 5 is monotonically increasing when
(a) x < −3
(b) | x | > 3
(c) x ≤ −3
(d) | x | ≥ 3

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Solution

(d) | x | ≥ 3

fx=x3-27x+5f'x=3x2-27 =3 x2-9For f(x) to be increasing, we must havef'x>03 x2-9>0x2-9>0 Since 3>0, 3 x2-9>0x2-9>0|x+3x-3>0x<-3 or x>3x>3

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