Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
π
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
2π
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
3π2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is Aπ2 Let f(x)=sin4x+cos4x =(sin2x+cos2x)2−2sin2xcos2x=1−4sin2xcos2x2=1−sin22x2=1−14(2sin22x)=1−(1−cos4x4)=34+14cos4x ∵ fundamental period of cosx=2π
Hence, fundamental period of function =2π4=π2