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Byju's Answer
Standard XII
Physics
Periodic Motion
Fundamental P...
Question
Fundamental Period of the function
f
(
θ
)
=
sin
θ
+
sin
2
θ
cos
θ
+
cos
2
θ
,
θ
∈
R
−
{
(
2
n
+
1
)
π
,
2
m
π
±
π
3
,
n
,
m
∈
Z
}
is
A
2
π
6
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B
π
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C
π
2
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D
2
π
3
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Solution
The correct option is
D
2
π
3
f
(
θ
)
=
sin
θ
+
sin
2
θ
cos
θ
+
cos
2
θ
=
2
sin
(
3
θ
2
)
cos
(
θ
2
)
2
cos
(
3
θ
2
)
cos
(
θ
2
)
=
tan
(
3
θ
2
)
We know that,
Period of
f
(
x
)
=
tan
(
a
x
+
b
)
is
π
|
a
|
So, period of
tan
(
3
θ
2
)
=
π
3
/
2
=
2
π
3
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0
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