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Question

Fundamental Period of the function f(θ)=sinθ+sin2θcosθ+cos2θ,θR{(2n+1)π,2mπ±π3,n,mZ} is

A
2π6
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B
π
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C
π2
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D
2π3
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Solution

The correct option is D 2π3
f(θ)=sinθ+sin2θcosθ+cos2θ=2sin(3θ2)cos(θ2)2cos(3θ2)cos(θ2)=tan(3θ2)

We know that,
Period of f(x)=tan(ax+b) is π|a|
So, period of tan(3θ2)=π3/2=2π3

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