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Byju's Answer
Standard XII
Chemistry
Valency and Oxidation State
Fundamental p...
Question
Fundamental period of the function
f
(
x
)
=
cos
(
2
π
{
2
x
}
)
is, where
{
x
}
fractional part of
x
A
1
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B
1
2
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C
2
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D
1
4
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Solution
The correct option is
A
1
2
Since period of
{
x
}
is
1
so period of
{
2
x
}
is
1
/
2
Thus, period of
f
(
x
)
is
1
/
2
.
Suggest Corrections
0
Similar questions
Q.
Period of
f
(
x
)
=
{
x
}
+
{
x
+
1
3
}
+
{
x
+
2
3
}
is equal to (where
{
.
}
denotes fraction part function )
Q.
Consider the function
f
(
x
)
=
sin
(
k
x
)
+
{
x
}
, where
{
x
}
represents the fractional part function
Statement 1:
f
(
x
)
is periodic for
k
=
m
π
, where
m
is a rational number
Statement 2: The sum of two periodic functions is always periodic
Q.
The fundamental period of the function
f
(
x
)
=
s
i
n
(
π
4
[
x
]
)
+
t
a
n
(
π
2
[
x
]
)
+
[
x
]
+
[
x
+
1
3
]
+
[
x
+
2
3
]
−
3
x
is
[
w
h
e
r
e
[
.
]
→
the greatest integer function
]
Q.
The fundamental period of the function
f
(
x
)
=
s
i
n
(
π
4
[
x
]
)
+
t
a
n
(
π
2
[
x
]
)
+
[
x
]
+
[
x
+
1
3
]
+
[
x
+
2
3
]
−
3
x
is
[
w
h
e
r
e
[
.
]
→
the greatest integer function
]
Q.
Consider
f
(
x
)
=
⎧
⎪ ⎪ ⎪
⎨
⎪ ⎪ ⎪
⎩
x
[
x
]
2
log
(
1
+
x
)
2
for
−
1
<
x
<
0
ln
e
x
2
+
2
√
{
x
}
tan
√
x
for
0
<
x
<
1
where [*] & {*} are the greatest integer function & fractional part function respectively, then -
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