Fundamental period of the function f(x)=(1+sinx)(1+secx)(1+cosx)(1+cosecx),x∈R−{(2n+1)π,(4m−1)π2,n,m∈Z} is
A
π2
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B
π
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C
2π
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D
1
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Solution
The correct option is Bπ f(x)=(1+sinx)(1+secx)(1+cosx)(1+cosecx) =(1+sinx)(1+1cosx)(1+cosx)(1+1sinx) =sinxcosx=tanx
Hence, fundamental period of f(x) is π.