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Question

Fundamental period of the function f(x)=(1+sinx)(1+secx)(1+cosx)(1+cosec x),xR{(2n+1)π,(4m1)π2,n,mZ} is

A
π2
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B
π
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C
2π
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D
1
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Solution

The correct option is B π
f(x)=(1+sinx)(1+secx)(1+cosx)(1+cosec x)
=(1+sinx)(1+1cosx)(1+cosx)(1+1sinx)
=sinxcosx=tanx
Hence, fundamental period of f(x) is π.

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