Furanose ring structure of fructose is due to hemiacetal formation between

C₁ and C₂

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C₂ and C₅

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C₂ and C₆

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C₁ and C₅

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Solution

The correct option is B
C₂ and C₅

Fructofuranose is formed by the hemiacetal linkage between $C_{2}$ and $C_{5}$ of the fructose molecule.

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Similar questions

Furanose ring structure of fructose is due to hemiacetal formation between

C_{1} = C_{5} = C_{3} = 2 μ F, C_{2} = C_{4} = 4 μ F

2 μ F

5 V

4 μ F

10 V

C_{1} = C_{2} = C_{3}

= 400 pF

C_{4} = C_{5} = C_{6} = 200 pF

X

Y

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