Question

Fusion of ${\mathrm{MnO}}_2$ along with $\mathrm{KOH}$ and ${\mathrm{O}}_2$ forms $\mathrm{X}$. Electrolytic oxidation of $\mathrm{X}$ yields $\mathrm{Y}$. $\mathrm{X}$ undergoes disproportionation reaction in acidic medium to ${\mathrm{MnO}}_2$ and $\mathrm{Y}$. The Manganese in $\mathrm{X}$ and $\mathrm{Y}$ is in the form $\mathrm{W}$ & $\mathrm{Z}$ respectively, then

• A. $\mathrm{W}$ & $\mathrm{Z}$ are coloured
• B. $\mathrm{W}$ is diamagnetic and $\mathrm{Z}$ is paramagnetic
• C. Both $\mathrm{W}$ & $\mathrm{Z}$ are tetrahedral in shape
• D. Both $\mathrm{W}$ & $\mathrm{Z}$ involve $\mathrm{p\pi }-\mathrm{d\pi }$ bonding for $\mathrm{\pi }$ bond

Answer 1

Answer: (A), (B), (D)

Both $\mathrm{W}$ & $\mathrm{Z}$ involve $\mathrm{p\pi }-\mathrm{d\pi }$ bonding for $\mathrm{\pi }$ bond

The above question can be contextualized as follows:

1. Since in the presence of $\mathrm{KOH}$, Manganese dioxide converted into manganate ion
2. Electrolytic oxidation of manganate ion converts into permanganate ion
3. The disproportionation of permanganate ion in acidic medium leads to Manganese dioxide and permanganate ion
4. The reaction explained in below diagram:

Therefore, the above points clearly explains the quandary of above question.