Question

Fusion reaction is given by ${}_6^{12}C{+}_6^{12}C{\to }_{10}^{20}Ne{+}_2^{4}He$.
If B.E. per nucleon for ${}_6^{12}C$ is X, B.E. per nucleon for ${}_{10}^{20}Ne$ is Y and B.E. per nucleon for ${}_2^{4}He$ is Z, then Q value of reaction is

• A. $24X-20Y-6Z$
• B. $Y+Z-X$
• C. $24X-10Y-2Z$
• D. $20Y+4Z-24X$

Answer 1

The correct option is D $20Y+4Z-24X$

$Q=B.E{.}_{prod}-B.E{.}_{reactant}$
$Q=20Y+4Z-24X$