Fusion reaction takes place at about:

3 \times 10^{2} K

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3 \times 10^{3} K

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3 \times 10^{4} K

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3 \times 10^{6} K

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Solution

The correct option is C $3 \times 10^{6} K$
$16 e v = 1.6 \times 10^{13} K$
So, using this nation with the energy released by Hydrogen fusion from
$Q = Δ m c^{2}$
gives us $T = 3.73 \times 10^{6} K$

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Similar questions

Q. Fusion reactions take place at about :

At what temperature does the rms speed of oxygen molecules equal the escape velocity of - (i) Earth, (ii) the Moon? Assume gravitational acceleration at the moon is 0.6g.

At what temperature does the rms speed of oxygen molecules equal the escape velocity of - (i) Earth, (ii) the Moon? The gravitational acceleration of the Moon is 0.6g.

Q. The reaction

[F e (C N S)_{6}]^{3 -} \to [F e F_{6}]^{3 -}

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Q. Consider the following reactions, which are carried out at the same temperature.

C H_{3} - B r + O H^{\oplus} E t O H - -- \to C H_{3} - O H + B r^{⊖} \dots (i) C H_{3} - B r + O H^{\oplus} D M S O - --- \to C H_{3} - O H + B r^{⊖} \dots (i i)

Which of the following statement is correct about these reactions?

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Fusion reaction takes place at about:

The correct option is C 3×106K16ev=1.6×1013K So, using this nation with the energy released by Hydrogen fusion from Q=Δmc2gives us T=3.73×106K

The correct option is C $3 \times 10^{6} K$
$16 e v = 1.6 \times 10^{13} K$
So, using this nation with the energy released by Hydrogen fusion from
$Q = Δ m c^{2}$
gives us $T = 3.73 \times 10^{6} K$