Question 85 (g)
Evaluate 64×92×25332×42×156
We have, 64×92×25332×42×156=(2×3)4×(32)2×(52)332×(22)2×(3×5)6=24×34×34×5632×24×36×56=24−4×34+4−2−6×56−6=20×30×50=1×1×1=1
Evaluate: 52 – 92 + 33 × 42 ÷ 24
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Question 85 (d)
Evaluate 34×123×3625×63
Question 85 (f)
Evaluate 154×18333×52×122