G is a graph on n vertices and 2n - 2 edges. The edges of G can be partitioned into two edge-disjiont spanning trees. Which of the following is NOT true for G ?
A
The minimum cut in G has at least 2 edges
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
There are at least 2 edge-disjoint paths between every pair of vertices
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
For every subset of k vertices, the induced subgraph has at most 2k - 2 edges
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
There are at least 2 vertex-disjoint paths between every pair of vertices
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution
The correct option is D There are at least 2 vertex-disjoint paths between every pair of vertices
Given graph G contains n vertices and 2n - 2 = 2(n-1) edges.
So spanning tree must contains 2n - 4 edges. If G can be partioned into two edge disjoint spanning tree.
Then for any tree
2e=∑ni=1di
belongs to a tree if each di is positive and e = n - 1
But in given problem e = 2n - 4 = 2(n-2)
So there are at least two vertex-disjoint paths between every pair of vertices.