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The Mid-Point Theorem

G is the cent...

Question

G is the centroid of triangle ABC. If AG=BC, then find the value of angle BGC.

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Solution

Angle BGD will be equal to angle GBD

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Similar questions

A B C

A B = A C = 5

B C = 6

G

△ A B C

A G

G

△ A B C

\frac{A B^{2} + B C^{2} + C A^{2}}{A G^{2} + B G^{2} + C G^{2}}

A B C

G

∠ A B C = 90^{o}

∠ B A C + ∠ B G C = 180^{o}

cos ∠ A C B

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B C = 6

Δ A B C

(1, - 4); (6, - 1); (- 1, - 2)

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