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Question

Question 58 (g)

Subtract:

x3y2+3x2y27xy3 from x4+y4+3x2y2xy3.

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Solution

We have,
x4+y4+3x2y2xy3(x3y3+3x2y27xy3)=x4+y4+3x2y2xy3x3y33x2y2+7xy3
On combining the like terms.
=x4+y4+3x2y23x2y2xy3+7xy3x3y3=x4+y4+6xy3x3y3


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