Question

Galileo writes that for angles of projection of a projectile at angles (45 + $\theta$) and (45 - $\theta$), the horizontal ranges described by the projectile are in the ratio of (if $\theta$ < 45)

• A. 2 : 1
• B. 1 : 2
• C. 1 : 1
• D. 2 : 3

Answer 1

The correct option is C

1 : 1

For angle $({45}^o-\theta ),R=\frac{u^{2}sin({90}^o–2\theta )}{g}=\frac{u^{2}cos2\theta }{g}$

For angle $({45}^o+\theta ),R=\frac{u^{2}sin({90}^o+2\theta )}{g}=\frac{u^{2}cos2\theta }{g}$