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B
a
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C
Aa
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D
aa
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Solution
The correct option is A A When individuals with genotypes AA (homozygous dominant) are crossed with aa (homozygous recessive) the gametes formed will be A, a. The F1 individual will have genotype (Aa). All plants will have axial flower due to the presence of dominant gene A. Now the selfing of F1 will give one homozygous dominant (AA), two heterozygous (Aa), and one homozygous recessive (aa).