Gas $A$ diffuses 2 times faster than gas $B$ . Ratio of their molecular weights is:

2 : 1

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4 : 1

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1 : 4

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1 : 2

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Solution

The correct option is C $1 : 4$
$\frac{r_{A}}{r_{B}} = \sqrt{\frac{M_{B}}{M_{A}}}$

$\frac{2 \times r_{B}}{r_{B}} = \sqrt{\frac{M_{B}}{M_{A}}}$

Thus, $\frac{M_{A}}{M_{B}} =$ $1 : 4$

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