Question

Gas at $300$ K is compressed to reduced its volume to half of it's volume, At what temperature will it become double of it's initial volume?

Answer 1

We know Charle's Law assuming constant pressure gives us,

$\frac{V_1}{T_1}=\frac{V_2}{T_2}$

Given,

$T_1=300K$, Let initial volume be V.

So,$V_1=\frac{V}{2}$ and $V_2=V$

Now on substituting these in the equation,

$⟹\frac{V}{300\times 2}=\frac{2V}{T_2}$

$⟹T_2=1200K$