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Properties of Water

Gas produced ...

Question

Gas produced after introduction of $H_{2}$ in the mixture?

H_{2} O

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C H_{4}

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C O_{2}

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N H_{3}

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Solution

The correct option is D $N H_{3}$
Given
Volume of $N_{2}$ , Alkane, $O_{2}$ is 10 ml
Solution
Reaction of $N_{2}$ , $C_{n} H_{2 n + 2}$ , $O_{2}$ gives $C O_{2}$
$C O_{2}$ is absorbed by KOH
Volume contracted = 2ml
Hence Volume of $C O_{2}$ = 2ml
Now in tube only $N_{2}$ and Alkane is left
When $N_{2}$ is reacted with excess of $H_{2}$ it forms $N H_{3}$ .
The correct option is D

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Similar questions

The volumes of gases $H_{2}, C H_{4}, C O_{2} a n d N H_{3}$ absorbed by 1 g of charcoal at 288 K are in the order:

M n O_{2} + H C l \to M n C l_{2} + C l_{2} + H_{2} O

N H_{4} C l + C a (O H)_{2} \to N H_{3} + C a C l_{2} + H_{2} O

B a C l_{2} + A l_{2} (S O_{4})_{3} \to B a S O_{4} + A l C l_{3}

N a A l O_{2} + H_{2} O + C O_{2} \to A l H_{3} + N a_{2} C O_{3}

N H_{3} + O_{2} \to N O + H_{2} O

Z n + H N O_{3} \to Z n (N O_{3})_{2} + N O_{2} + H_{2} O

H_{2} S + O_{2} \to H_{2} O + S O_{2}

P b O + C \to P b + C O_{2}

B a C l_{2} + H_{2} S O_{4} \to B a S O_{4} + H C l

C H_{4} + O_{2} \to C O_{2} + H_{2} O

C O_{2} + H_{2} O + H_{2}

C H_{4} + H_{2} O

C H_{4} (g) + H_{2} O

3 F e + 4 H_{2} O (s t e a m)

H_{2}, H_{2} O, C H_{4} a n d N H_{3}

C H_{4}, N H_{3}, H_{2} O, H F

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