Gaseous hydrogen initially at STP in a container of volume 5- 10-3 m3 is cooled by 55 K- Find the amount of heat lost by the gasin J-

Initially in standard conditions the gas pressure is nbsp; P=10^5Pa Gas temperature is T=273 K Gas volume is V=5×10^ 3 m^3 If n moles of gas are there, then ...

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Standard XII

Chemistry

Internal Energy

Gaseous hydro...

Question

Gaseous hydrogen initially at STP in a container of volume $5 \times 10^{- 3} m^{3}$ is cooled by $55 K$ . Find the amount of heat lost by the gas(in $J$ ).

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Solution

Initially in standard conditions the gas pressure is
$P = 10^{5}$ Pa
Gas temperature is $T = 273 K$
Gas volume is $V = 5 \times 10^{- 3} m^{3}$
If n moles of gas are there, then from gas law, we have
$P V = n R T$
$n = \frac{P V}{R T} = \frac{10^{5} \times 5 \times 10^{- 3}}{8.314 \times 273} = 0.22 m$ .
Thus change in internal energy in a process is given as
$Δ U = \frac{f}{2} n R Δ T$
$= \frac{5}{2} \times 0.22 \times 8.314 \times 55 = 251.5 J$ .
As gas is enclosed in a container its volume remains constant during the process thus work done in this process is zero and according to first law of thermodynamics, we have $Q = Δ U = - 251.5 J$

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Gaseous hydrogen initially at STP in a container of volume 5×10−3 m3 is cooled by 55 K. Find the amount of heat lost by the gas(in J).

Gaseous hydrogen initially at STP in a container of volume $5 \times 10^{- 3} m^{3}$ is cooled by $55 K$ . Find the amount of heat lost by the gas(in $J$ ).