Gastric juice contains 3.0g of $H C l$ per litre. If a person produces 2.44 litre of gastric juice per day. How many antacid tablets each containing 400 mg of $A l$ ( $O H)_{3}$ are needed to neutralize all the $H C l$ produced in one day ?

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Solution

The correct option is B
13

geq of $H C l$ = $\frac{3}{36.5} 2.44 \approx 0.2$ = geq of $A l$ ( $O H)_{3}$

Weight of $A l (O H)_{3}$ = $\frac{0.2 \times 78}{3}$ = $5.2 g$ = $5200 m g$

No. of tablets = $\frac{5200}{400}$ = $13$

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Gastric juice contains 3.0g of $H C l$ per litre. If a person produces 2.44 litre of gastric juice per day. How many antacid tablets each containing 400 mg of $A l$ ( $O H)_{3}$ are needed to neutralize all the $H C l$ produced in one day? Choose the nearest answer.

Q. Gastric juice contains

0.03

moles

H C l

of per liter. If a person produces

2.5

L of gastric juice per day. How many antacid tablets each containing

400

mg of

A l (O H)_{3}

are needed to neutralize all the

H C l

produced in one day?

A juice factory produces 180 litres of juice everyday. If the juice carton has the following measurements: height = 12 cm, breadth = 3 cm and length = 5 cm, how many containers will be filled in a day? [4 MARKS]

Q. The capacity of human stomach to release gastric juice per day is

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Gastric juice contains 3.0g of HCl per litre. If a person produces 2.44 litre of gastric juice per day. How many antacid tablets each containing 400 mg of Al(OH)3 are needed to neutralize all the HCl produced in one day ?

The correct option is B 13 geq of HCl = 336.5 2.44≈0.2 = geq of Al(OH)3 Weight of Al(OH)3 = 0.2 × 783 = 5.2g = 5200mg No. of tablets =5200400 = 13

Gastric juice contains 3.0g of $H C l$ per litre. If a person produces 2.44 litre of gastric juice per day. How many antacid tablets each containing 400 mg of $A l$ ( $O H)_{3}$ are needed to neutralize all the $H C l$ produced in one day ?

The correct option is B
13

geq of $H C l$ = $\frac{3}{36.5} 2.44 \approx 0.2$ = geq of $A l$ ( $O H)_{3}$

Weight of $A l (O H)_{3}$ = $\frac{0.2 \times 78}{3}$ = $5.2 g$ = $5200 m g$

No. of tablets = $\frac{5200}{400}$ = $13$