Question

Gaussian surface obtains a measure of the electric charge within the surface

• A. depending how that internal charge is configured.
• B. no matter how that internal charge is configured.
• C. and may sometimes depend how that internal charge is configured
• D. None of these

Answer 1

The correct option is B no matter how that internal charge is configured.

From Gauss Law, which states that electric flux $\left(\varphi \right)$ through any closed surface $\left(S\right)$ in free space is equal to $\frac{1}{{\epsilon }_0}$ times the total charge $\left(q_0\right)$ enclosed by the surface i.e, $\varphi =\oint \overrightarrow{E}.\overrightarrow{dS}=\frac{q_{enclosed}}{{\epsilon }_0}$

${\epsilon }_0$ is the permittivity of free space. The flux through the surface depends only on the magnitude of charge and independent of how that charge enclosed is configured.