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Standard XII

Physics

Thermodynamic Processes

Gay-Lussac's ...

Question

Gay-Lussac's law i.e, dependence of pressure of ideal gas with temperature in $^{o} C$ can be expressed as $P_{t} = a + b t$ where

a = P_{0}

and t in

^{o} C

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b = {(\frac{\partial P}{\partial t})}_{V}

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b = [\frac{P_{0}}{273.15}]

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P_{T} = K T

, where T is in K

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Solution

The correct options are
A $a = P_{0}$ and t in $^{o} C$
B $P_{T} = K T$ , where T is in K
C $b = {(\frac{\partial P}{\partial t})}_{V}$
D $b = [\frac{P_{0}}{273.15}]$
Gay Lussac's law:
It states "at constant volume, the pressure of a given mass of a gas is directly proportional to the absolute temperature of the gas".
$P \propto T$ .
$\frac{P}{T} = c o n s t a n t (K)$

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Gay-Lussac's law i.e, dependence of pressure of ideal gas with temperature in oC can be expressed as Pt=a+bt where

The correct options are A a=P0 and t in oC B PT=KT, where T is in K C b=(∂P∂t)V D b=[P0273.15]Gay Lussac's law:It states "at constant volume, the pressure of a given mass of a gas is directly proportional to the absolute temperature of the gas".P∝T.PT=constant(K)

Gay-Lussac's law i.e, dependence of pressure of ideal gas with temperature in $^{o} C$ can be expressed as $P_{t} = a + b t$ where