Geeta read $\frac{3}{8}$ of a book on one day and $\frac{4}{5}$ of the remaining on another day. Find the total number of pages in the book, if $60$ pages are left unread after the second day.

480

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400

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430

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500

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Solution

The correct option is C $480$
Portion of the book left unread after one day $= 1 -$ portion of the book read on one day
$= 1 - \frac{3}{8}$
$= \frac{8 - 3}{8}$
$= \frac{5}{8}$
Portion of the book read on another da} $= \frac{4}{5}$ of portion of the book left unread after one day}
$= \frac{4}{5} \times \frac{5}{8}$
$= \frac{1}{2}$
Portion of the book left unread after two days $= 1 -$ (portion of book read on one day $+$ portion of book read on another day
$= 1 - (\frac{3}{8} + \frac{1}{2})$
$= 1 - \frac{7}{8}$
$= \frac{1}{8}$
Let there be ' $x$ ' number of pages in the book
According to question,
$\frac{1}{8} of x = 60$
$⟹ x = 480$
Therefore, total number of page $= 480$

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