Gene P and Q are necessary for normal hearing. A deaf man marries a deaf woman and all their children have normal hearing; the genotypes of parents are
A
PPqq × PPqq
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B
Ppqq × ppQq
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C
PPqq × ppQQ
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D
ppQQ × ppQq
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Solution
The correct option is B PPqq × ppQQ Gene P and Q are necessary for normal hearing. A deaf man marries a deaf woman. They produce children who are capable of normal hearing. In order to hear properly, all the offsprings must have delivered one dominant gene of P and Q from their parents. So, the correct genotype of the mother and father will be PPqq x ppQQ.