Question

General electronic configuration of actionoids is $(n-2)f^{1-14}(n-1)d^{0-2}n{s}^2$. Which of the following actinoids have one electron in 6d orbital?

• A. U (Atomic no. 92)
• B. Np (Atomic no. 93)
• C. Pu (Atomic no. 94)
• D. Am (Atomic no. 95)

Answer 1

Answer: (A), (B)

The correct options are
A U (Atomic no. 92)
B Np (Atomic no. 93)

For Uranium, teh electronic configuration is:

$\left[Rn\right]5f^{3}6d^{1}7s^2$

And for Neptunium:
$\left[Rn\right]5f^{4}6d^{1}7s^2$