wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

General solution for |sinx|=cosx is-

A
2nπ+π4,nϵI
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
2nπ±π4,nϵI
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
nπ±π4,nϵI
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
None of these
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is D nπ±π4,nϵI

Consider the given expression.

|sinx|=cosx

When sinx<0,

sinx=cosx

tanx=1

x=nππ4

When sinx>0,

sinx=cosx

tanx=1

x=nπ+π4

Therefore, required set of values are,

x=nπ±π4; nI

Hence, this is the required result.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Formation of Differential Equation
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon