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Question

General solution for |sinx|=cosx is-

A
2nπ+π4,nϵI
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B
2nπ±π4,nϵI
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C
nπ±π4,nϵI
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D
None of these
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Solution

The correct option is D nπ±π4,nϵI

Consider the given expression.

|sinx|=cosx

When sinx<0,

sinx=cosx

tanx=1

x=nππ4

When sinx>0,

sinx=cosx

tanx=1

x=nπ+π4

Therefore, required set of values are,

x=nπ±π4; nI

Hence, this is the required result.

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