General solution of tan 5 x - 2 x isa n - 7- 2- n - Zb x-n - 7- 3- n - Zc x-n - 7- 14- n - Zd x-n - 7- 14- n - Z

(c) nbsp;x=n #160; #960;7+ #960;14, #160;n #160; #8712; #160;Z Given: nbsp;tan5x #160;= #160;cot2x #8658;tan5x #160;= #160;tan # ...

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Basic Trigonometric Identities

General solut...

Question

General solution of $\tan 5 x = \cot 2 x$ is
(a) $\frac{n π}{7} + \frac{π}{2}, n \in Z$

(b) $x = \frac{n π}{7} + \frac{π}{3}, n \in Z$

(c) $x = \frac{n π}{7} + \frac{π}{14}, n \in Z$

(d) $x = \frac{n π}{7} - \frac{π}{14}, n \in Z$

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\tan 5 θ = \cot 2 θ

\frac{n π}{7} + \frac{π}{2}, n \in Z

θ = \frac{n π}{7} + \frac{π}{3}, n \in Z

θ = \frac{n π}{7} + \frac{π}{14}, n \in Z

θ = \frac{n π}{7} - \frac{π}{14}, n \in Z

\sqrt{3} \cos x + \sin x = \sqrt{2}

n π + {(- 1)}^{n} \frac{π}{4}, n \in Z

{(- 1)}^{n} \frac{π}{4} - \frac{π}{3}, n \in Z

n π + \frac{π}{4} - \frac{π}{3}, n \in Z

n π + {(- 1)}^{n} \frac{π}{4} - \frac{π}{3}, n \in Z

7 \cos^{2} x + 3 \sin^{2} x = 4

x = 2 n π \pm \frac{π}{6}, n \in Z

x = 2 n π \pm \frac{2 π}{3}, n \in Z

x = n π \pm \frac{π}{3}, n \in Z

\sqrt{3} \cos θ + \sin θ = \sqrt{2}

n π + {(- 1)}^{n} \frac{π}{4}, n \in Z

{(- 1)}^{n} \frac{π}{4} - \frac{π}{3}, n \in Z

n π + \frac{π}{4} - \frac{π}{3}, n \in Z

n π + {(- 1)}^{n} \frac{π}{4} - \frac{π}{3}, n \in Z

\sqrt{3} \sin x + \cos x = \sqrt{3}

x = n π + {(- 1)}^{n} \frac{π}{4} + \frac{π}{3}, n \in Z

x = n π + {(- 1)}^{n} \frac{π}{3} + \frac{π}{6}, n \in Z

x = n π \pm \frac{π}{6}, n \in Z

x = n π \pm \frac{π}{3}, n \in Z

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