The correct option is C a straight line or a parabola
Substitute p=dydx, the given equation can be written as y=px+1/p. Differentiating w.r.t. x, we have
p=dydx=p+xdpdx−1p2dpdx
⇒(x−(1/p2))dpdx=0⇒p2=1x or dpdx=0
If dpdx=0 then p= constant =c putting this value in given equation, we get y=cx+1/c which represents a straight line. If p2=1/x then y2=(px+1/p)2=p2x2+1/p2+2x=1xx2+x+2x=4x, which represents a parabola.